檢視 SCJP 1.6版考題 044 的原始碼

 1. class Employee{
 2.   String name; double baseSalary;
 3.     public Employee(String name, double baseSalary){
 4.     this.name = name;
 5.     this.baseSalary = baseSalary;
 6.   }
 7. }
 8. public class SalesPerson extends Employee{
 9.   double commission;
 10.  public SalesPerson(String name,
 11.      double baseSalary, double commission){
 12.    //insert code here
 13.  }
 14.}
 
 
 Which two code fragments, inserted independently at line 12, will compile? (Choose two.)
 
   A. super(name, baseSalary);
   B. this.commission = commission;
   C. super();
      this.commission = commission;
   D. this.commission = commission;
      super();
   E. super(name, baseSalary);
      this.commission = commission;
   F. this.commission = commission;
      super(name, baseSalary);
   G. super(name, baseSalary, commission);



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<span style="font-size:medium;">解答</span>

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<span style="font-size: medium;">Ans:A  E   </span>

<span style="font-size:medium;"> 解說:
 由於父類別Employee沒有“無參數”的建構子，所以本程式要能編譯，必須要避免編譯器為SalesPerson的建構子加上super()，
 於是就加A/E，加上明確的呼叫父類別的建構子Employee(String name, double baseSalary)
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{{SCJP 1.6版考題講解}}