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SCJP 1.6版考題 173 - 修訂歷史
2026-05-30T00:13:30Z
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Ikk：新頁面: Given: 11. public class Yikes{ 12. 13. public static void go(Long n){System.out.print("Long ");} 14. public static void go(Short n){System. outprint("Short ");} 15. public ...
2013-03-30T02:02:30Z
<p>新頁面: Given: 11. public class Yikes{ 12. 13. public static void go(Long n){System.out.print("Long ");} 14. public static void go(Short n){System. outprint("Short ");} 15. public ...</p>
<p><b>新頁面</b></p><div> Given:<br />
11. public class Yikes{<br />
12.<br />
13. public static void go(Long n){System.out.print("Long ");}<br />
14. public static void go(Short n){System. outprint("Short ");}<br />
15. public static void go(int n){System.out.print("int ");}<br />
16. public static void main(String[] args){<br />
17. short y = 6;<br />
18. long z = 7;<br />
19. go(y);<br />
20. go(z);<br />
21. }<br />
22. }<br />
<br />
What is the result?<br />
A. int Long<br />
B. Short Long<br />
C. Compilation fails.<br />
D. An exception is thrown at runtime.<br />
<br />
<div class="toccolours mw-collapsible mw-collapsed"><br />
<span style="font-size:medium;">解答</span><br />
<br />
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<div class="mw-collapsible-content"><br />
<span style="font-size: medium;">Ans: A </span><br />
<br />
<span style="font-size:medium;"> 解說:<br />
go(y)會代15行的go方法，short可以自動提升至int <br />
(那為什麼不採取Short的第14行go？變成Short物件會比單純16位元轉成32位元要複雜)<br />
go(z)z是long，不可能代入15行的go，所以就用13行的go，z會auto-boxing成Long物件<br />
<br />
</span> <br />
</div></div><br />
{{SCJP 1.6版考題講解}}</div>
Ikk