"SCJP 1.6版考題 044" 修訂間的差異
出自 陳富國維基館
(新頁面: 1. class Employee{ 2. String name; double baseSalary; 3. public Employee(String name, double baseSalary){ 4. this.name = name; 5. this.baseSalary = baseSalary; 6. ...) |
(無差異)
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於 2013年3月30日 (六) 07:42 的最新修訂
1. class Employee{ 2. String name; double baseSalary; 3. public Employee(String name, double baseSalary){ 4. this.name = name; 5. this.baseSalary = baseSalary; 6. } 7. } 8. public class SalesPerson extends Employee{ 9. double commission; 10. public SalesPerson(String name, 11. double baseSalary, double commission){ 12. //insert code here 13. } 14.} Which two code fragments, inserted independently at line 12, will compile? (Choose two.) A. super(name, baseSalary); B. this.commission = commission; C. super(); this.commission = commission; D. this.commission = commission; super(); E. super(name, baseSalary); this.commission = commission; F. this.commission = commission; super(name, baseSalary); G. super(name, baseSalary, commission);
解答
Ans:A E
解說:
由於父類別Employee沒有“無參數”的建構子,所以本程式要能編譯,必須要避免編譯器為SalesPerson的建構子加上super(), 於是就加A/E,加上明確的呼叫父類別的建構子Employee(String name, double baseSalary)
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