SCJP 1.6版考題 136

Given:
11. public static void main(String[] args){
12.   try{
13.     args = null;
14.     args[0] = "test";
15.     System.out.println(args[0]);
16.   }catch(Exception ex) {
17.     System.out.println("Exception");
18.   }catch(NullPointerException npe){
19.     System.out.println("NullPointerException");
20.   }
21. }
 

What is the result?
 A. test
 B. Exception
 C. Compilation fails.
 D. NullPointerException

解答

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Ans: C

解說: 子類別例外應先於父類別例外catch