SCJP 1.6版考題 102

Given:
10. interface Foo{int bar();}
11. public class Sprite{
12.   public int fubar(Foo foo){return foo.bar();}
13.   public void testFoo(){
14.     fubar(
15.       //insert code here
16.     );
17.   }
18. }


Which code, inserted at line 15, allows the class Sprite to compile?
  A. Foo{public int bar(){return 1;}}
  B. new Foo{public int bar(){return 1;}}
  C. new Foo(){public int bar(){return 1;}}
  D. new class Foo{public int bar(){return 1;}}

解答

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Ans: C

解說: 14行呼叫fubar，參數要帶入一個Foo的物件參考，因此使用new Foo(){…}形式，建立一個Foo物件。